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Q.

9 grams of a trivalent metal combines with 8 grams oxygen. What is the atomic weight of the metal?

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a

9

b

54

c

18

d

27

answer is B.

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Detailed Solution

WM = 9g
W_{O_2} = 8g
\large \frac{{{W_M}}}{{{W_{{O_2}}}}}\; = \;\frac{{{E_M}}}{{{E_{{O_2}}}}}
\large \frac{9}{8}\; = \;\;\frac{{{E_M}}}{8}
Valency of metal = 3
Aw = EW x Valency
Aw of metal = 9 x 3
                  = 27

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