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965 A current is passed for 5 minute in molten solution and 27 g of metal is deposit at cathode. The possible mot solution is
[Assume electrode are inert and Faraday = 96500 C. Current efficiency (process is 100% ]

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All of these

AlCl₃

MgCl₂

NaCl

answer is C.

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Detailed Solution

Given i = 965 A and time (t) = 5 min = 300 sec

Charge (Q) = it = 289500 C

Number of faraday given ⇒ 965 $\times$ 5 $\times$ 60 = 3F

So, number of equivalent of metal deposit = 3

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