$$\begin{gathered} 96\cos \frac{\mathrm{\pi }}{33}\cos \frac{2\mathrm{\pi }}{33}\cos \frac{4\mathrm{\pi }}{33}\cos \frac{8\mathrm{\pi }}{33}\cos \frac{16\mathrm{\pi }}{33} \\ Let \frac{\mathrm{\pi }}{33}=\alpha \\ 96\cos \alpha \cdot \cos 2\alpha \cdot \cos 4\alpha \cdot \cos 8\alpha \cdot \cos 16\alpha \end{gathered}$$

$\text{By formula given expression }=96\cdot \frac{\sin \left(2^5\cdot \frac{\pi }{33}\right)}{2^5\cdot \sin \left(\frac{\pi }{33}\right)}=3$