99% of a 1st order reaction completed in 2.303minutes.What is the rate constant and half-life of the reaction

For $1^{\mathrm{st}}$order reaction

${\mathrm{t}}_{99\%}=2.303 \min \mathrm{then} {\mathrm{t}}_{1/2}?$

${\mathrm{t}}_{99\%}=\frac{4.606}{\mathrm{K}}$

$K=\frac{4.606}{{\mathrm{t}}_{99\%}}=\frac{4.606}{2.303}=2$

Then ${\mathrm{t}}_{1/2}=\frac{0.693}{\mathrm{K}}=\frac{0.693}{2}=0.3465 \min$