A 100 kg Man jumps into swimming pool from a height of 5 m it takes 0.4 second the water to reduce his velocity to zero. What is the average force exerted by water on the Man ? take $\text{g}=10{\text{ms}}^{-2}$

Mass = 100 kg,  h = 5 m, t = 0.4 s, v = 0,  F = ?

            Initial velocity of mass on water is

            $\text{u}=\sqrt{\text{2gh}}$

                $\text{u}=\sqrt{\text{2}\times \text{10}\times \text{5}}$

                $\text{u}=10{\text{ms}}^{-1}$

            $\text{a}=\frac{\text{v}-\text{u}}{\text{t}}=\frac{10-0}{0.4}=\frac{100}{4}=5{\text{ms}}^{-2}$

                $\text{F}=100\times 25$

                $\text{F}=2500\text{N}$