(a→-b→)×(a→+b→) is equal to

(a¯−b¯)×(a¯+b¯)=a¯×a¯+a¯×b¯−b¯×a¯−b¯×b¯=0¯+(a¯×b¯)−(−(a¯×b¯))−0¯=2(a¯×b¯)

(a→-b→)×(a→+b→) is equal to

(a¯−b¯)×(a¯+b¯)=a¯×a¯+a¯×b¯−b¯×a¯−b¯×b¯=0¯+(a¯×b¯)−(−(a¯×b¯))−0¯=2(a¯×b¯)

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$(\vec{a} - \vec{b}) \times (\vec{a} + \vec{b})$ is equal to

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$0$

$(\vec{a} \times \vec{b})$

2 $(\vec{a} \times \vec{b})$

$| a |^{2} + | b |^{2}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} (\bar{a} - \bar{b}) \times (\bar{a} + \bar{b}) = \bar{a} \times \bar{a} + \bar{a} \times \bar{b} - \bar{b} \times \bar{a} - \bar{b} \times \bar{b} \\ = \bar{0} + (\bar{a} \times \bar{b}) - (- (\bar{a} \times \bar{b})) - \bar{0} = 2 (\bar{a} \times \bar{b}) \end{array}$