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Q.

A block of mass m is resting on the floor of a lift. The coefficient of friction between the block and the floor is $μ$ . When the lift is falling freely, the limiting frictional force between block and surface is

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a

μ m g

b

mg

c

Zero

d

\frac{μ m g}{2}

answer is D.

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Detailed Solution

μ_{k} = ?

$f_{k} = μ_{k} N,a = {4m/s}^{2}$

$f_{k} = μ_{k} mg$

$- ma = μ_{k} mg$

$a = - μ_{k} g$

$4 = - μ_{k} \times 10$

$μ_{k} = \frac{4}{10}$

$μ_{k} = 0.4$

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A block of mass m is resting on the floor of a lift. The coefficient of friction between the block and the floor is μ . When the lift is falling freely, the limiting frictional force between block and surface is