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Q.

A body is projected at t=0 with a velocity 10 ms−1 at an angle of 600 with the horizontal. The radius of curvature of its trajectory at t=1s is R. Neglecting air resistance and taking acceleration due to gravityg=10 ms−2 , the value of R is

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a

10.3 m

b

2.8 m

c

2.5 m

d

5.1 m

answer is A.

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Detailed Solution

At t=1s

Vy=53−10×1

V=25+(53−10)2

Vx=5

=25+75+100−1003=200−1003=5.11

rc=v2gcosϕ=v2guxv=v3gux=(5.11)310×5=2.77m

 

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