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A body is projected vertically up with certain velocity. The ratio of velocity of projection to velocity at a point in its path is 6:5. The ratio of potential to kinetic energies at that point is

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11:25

1:4

9:25

11:36

answer is D.

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Detailed Solution

$\frac{u}{v} = \frac{6}{5} \Rightarrow \frac{u^{2}}{v^{2}} = \frac{36}{25}$

K. E at that point = $\frac{25}{36} \times$ Initial K.E

P. E at that point = $(1 - \frac{25}{36}) \times$ initial K.E

= $\frac{11}{36} \times K E_{i}$

$\frac{P E}{K E} = \frac{\frac{11}{36}}{\frac{25}{36}} = 11 : 25$

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