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A body of mass 15kg is raised from certain depth. If the workdone in raising it by 5m is 870J, its velocity at this position is $(g = 10 m s^{- 2})$

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$1 m s^{- 1}$

$8 m s^{- 1}$

$4 m s^{- 1}$

$2 m s^{- 1}$

answer is B.

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Detailed Solution

$w = m g h + \frac{1}{2} m v^{2}$

$870 = 15 \times 10 \times 5 + \frac{1}{2} \times 15 v^{2}$

$870 = 750 + \frac{15}{2} v^{2}$

$120 = \frac{15}{2} v^{2} \Rightarrow v^{2} = 16 \Rightarrow v = 4 m s^{- 1}$

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