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Q.

A body of mass $2 k g$ is projected vertically up with a velocity of $100 m s^{- 1}$ . If it rises to a height of $400 m,$ the energy utilized to overcome friction is $(g = 10 m s^{- 2})$

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a

$10 K J$

b

$8 K J$

c

$1 K J$

d

$2 K J$

answer is D.

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Detailed Solution

$w = \frac{1}{2} m u^{2} - m g h$

$= \frac{1}{2} \times 2 \times 100 \times 100 - 2 \times 10 \times 400$

$= 2000 = 2 k J$

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