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Q.

A body of mass 600 g slides on a rough horizontal surface. If the frictional force is 2 N, then the magnitude of reaction is $(g = 10 {ms}^{- 2})$

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a

2 \sqrt{10} N

b

5 \sqrt{10} N

c

6N

d

5N

answer is D.

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Detailed Solution

Question Image

$f = 2 N$

$R = ?$

$N = mg = 0 .6 \times 10N$

$N = 6N$

$\sqrt{N^{2} + f^{2}}$

$R = \sqrt{6^{2} + 2^{2}}$

$= \sqrt{36 + 4} = \sqrt{40}$

$R = 2 \sqrt{10} N$

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