A body of mass M is placed at the centre of a uniform spherical shell of equal mass and radius ‘a’. The gravitational potential at a point ‘p’ at a distance $\frac{a}{2}$ from the centre is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

\frac{2GM}{a}

- \frac{3GM}{a}

\frac{4GM}{a}

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Gravitational potential at the point P due to the particle at the centre is

$V_{1} = - \frac{GM}{R} = - \frac{2GM}{a} R = a/2$

Gravitational potential at ‘p’ due to spherical shall is $V_{2} = - \frac{GM}{a}$

$V = V_{1} + V_{2}$

$= - \frac{2GM}{a} - \frac{GM}{a} = - \frac{3GM}{a}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE