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Q.

A body of mass m is taken from the earth surface to a height equal to the radius R of earth. If ‘g’ is the acceleration due to gravity at the surface of the earth then change in the P.E of the body is

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a

2mgR

b

14mgR

c

12mgR

d

mgR

answer is B.

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Detailed Solution

P.E=mgR

P.Ef=−GMmR+h   

=−GMm2R×RR

=−GMR2×mR2               (∵GMR2=g)

=−gmR2

ΔP.E=−gmR2+mgR=12mgR

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