A body, starting from rest and moving with a constant acceleration ,covers 10 m in the first second. The distance travelled by it in the second is    

Solution:

• Initial velocity, u = 0 (from rest)
• Let acceleration = a
• Distance in first second, S₁ = u + (1/2)a(1)² = (1/2)a = 10 m. ⇒ a = 20 m/s²
• Distance in 2 seconds, S(2) = u × 2 + (1/2)a(2)² = 0 + 10 × 4 = 40 m
• Distance in 2^nd second = S(2) - S(1) = 40 m - 10 m = 30 m

Final Answer: The distance travelled by the body in the 2^nd second is 30 m.