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Q.

A bomb explodes in air when it has a horizontal speed of v. It breaks into two identical pieces of equal mass. If one goes vertically up at a speed of 4v. Find the velocity of other immediately after the explosion

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a

2vi^−4vj^

b

2vi^+4vj^

c

4vi^+2vj^

d

4vi^−2vj^

answer is A.

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Detailed Solution

momentum before collision = momentum after explosion

mvi=m24vj+m2v1

vi=4vj+v12

2vi−4vj=v1

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