(A) : Boric acid burnt with ethyl alcohol in green edged flame.
(R) : Boric acid when burnt with ethyl alcohol it forms tri ethyl orthoborate.

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(A) is true but (R) is false

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are false

Both (A) and (R) are true and (R) is not the correct explanation of (A)

answer is A.

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Detailed Solution

In the presence of concentrated sulphuric acid, Boric acid reacts with ethyl alcohol to produce triethyl borate.
When the vapours of triethyl borate are ignited, they produce a green-edged flame. This property is used as a qualitative test to identify boric and borates in the given compound.

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