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Q.

(A) : Both N2 and NO+ are diamagnetic substances.
(R) : Unpaired electrons are absent both in N2 and NO+.

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a

Both (A) and (R) are true and (R) is the correct explanation of (A)

b

Both (A) and (R) are true but (R) is not the correct explanation of (A)

c

(A) is true but (R) is false

d

Both (A) and (R) are false

answer is A.

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Detailed Solution

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Total no. of e in NO+=7+8−1=14

Total no. of e in N2=7+7=14

Therefore. both are isoelectronic.

Due to the absence of unpaired electrons in NO+ and N2, both are diamagnetic in nature.

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(A) : Both N2 and NO+ are diamagnetic substances.(R) : Unpaired electrons are absent both in N2 and NO+.