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Q.

A bullet of mass 2 g travelling with a velocity of 500ms1 is fired into a block of wood of mass 1 kg suspended from a string of 1m length. When the bullet penetrates the block of wood and comes out with a velocity of100ms1 , find the vertical height through which the block of wood will rise (assuming the value of g to be10ms2 )

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a

3.2 m

b

0.32m

c

0.032 m

d

0.0032m

answer is A.

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Detailed Solution

m1=2g=0.002kg,u1=500m/s,v1=100m/s

m2=1kg,u2=0m/s,v2=?

m1v1+m2v2=m1u1+m2u2

(0.002)100+1(v2)=0.002(500)+1(0)

0.2+v2=1

v2=0.8m/s

T.E at A = T.E at B

12mv2+0=0+mgh

12(0.64)=10(h)

h=0.032m

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A bullet of mass 2 g travelling with a velocity of 500 ms−1 is fired into a block of wood of mass 1 kg suspended from a string of 1m length. When the bullet penetrates the block of wood and comes out with a velocity of100 ms−1 , find the vertical height through which the block of wood will rise (assuming the value of g to be10 ms−2 )