A carnot engine operating between temperatures T1 and T2 has efficiency 16 . When T2 is lowered by 62K , its efficiency increases to 13 . Then T1 and T2 are, respectively

1=T2T1=16; T2T1=56→ (1) (1) in (2) 1−(T2−62T1)=13 → (2) 1−T2T1+62T1=13⇒16+62T1=13⇒62T1=16 ⇒T1=62×6=372k and T2=56T1=310k

A carnot engine operating between temperatures T1 and T2 has efficiency 16 . When T2 is lowered by 62K , its efficiency increases to 13 . Then T1 and T2 are, respectively

1=T2T1=16; T2T1=56→ (1) (1) in (2) 1−(T2−62T1)=13 → (2) 1−T2T1+62T1=13⇒16+62T1=13⇒62T1=16 ⇒T1=62×6=372k and T2=56T1=310k

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A carnot engine operating between temperatures $T_{1}$ and $T_{2}$ has efficiency $\frac{1}{6}$ . When $T_{2}$ is lowered by $62 K$ , its efficiency increases to $\frac{1}{3}$ . Then $T_{1}$ and $T_{2}$ are, respectively

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$330 K$ and $268 K$

$310 K$ and $248 K$

$372 K$ and $310 K$

$372 K$ and $330 K$

answer is C.

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$1 = \frac{T_{2}}{T_{1}} = \frac{1}{6}; \frac{T_{2}}{T_{1}} = \frac{5}{6} \to (1)$ $(1) i n (2)$

$1 - (\frac{T_{2} - 62}{T_{1}}) = \frac{1}{3} \to (2)$

$1 - \frac{T_{2}}{T_{1}} + \frac{62}{T_{1}} = \frac{1}{3} \Rightarrow \frac{1}{6} + \frac{62}{T_{1}} = \frac{1}{3} \Rightarrow \frac{62}{T_{1}} = \frac{1}{6}$

$\Rightarrow T_{1} = 62 \times 6 = 372 k$ and $T_{2} = \frac{5}{6} T_{1} = 310 k$

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A carnot engine operating between temperatures T1 and T2 has efficiency 16 . When T2 is lowered by 62K , its efficiency increases to 13 . Then T1 and T2 are, respectively

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A carnot engine operating between temperatures $T_{1}$ and $T_{2}$ has efficiency $\frac{1}{6}$ . When $T_{2}$ is lowered by $62 K$ , its efficiency increases to $\frac{1}{3}$ . Then $T_{1}$ and $T_{2}$ are, respectively