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Q.

A Carnot engine working between 300K and 600K has work output of 800 J per cycle. What is amount of heat energy supplied to the engine from source per cycle (in J/cycle)

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a

1000

b

1600

c

1800

d

2000

answer is D.

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Detailed Solution

$η = \frac{T_{1} - T_{2}}{T_{1}} = \frac{W}{Q} Q = (\frac{T_{1}}{T_{1} - T_{2}}) W$

$= \frac{600}{(600 - 300)} \times 800 = 1600$

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