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Q.

A certain balloon maintains an internal gas pressure of P0=100  kPa  until the volume reaches V0=20m3 . Beyond a volume of 20m3 , the internal pressure varies as P=P0+2k(VV0)2  where P  is in kPa,V  is in m3  and k  is a constant (k=1kPa/m3) . Initially the balloon contains helium gas at 200C , 100kPa  with a 15m3  volume. The balloon is then heated until the volume becomes 25m3  and the pressure is 150 kPa. Assume ideal gas behaviour for helium. The work done by the balloon for the entire process in kJ  is

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a

1256

b

1414

c

1083 

d

1512

answer is C.

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Detailed Solution

Work done by the balloon W=15m320m3P0dV+20m325m3pdV

 =15m320m3P0dV+20m325m3[P0+2(VV0)2]dV

                        =[100×5+100×5+2×(2520)33]kJ=1083kJ       

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