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A convex lens of focal length 40 cm, a concave lens of focal length 40 cm and a concave lens of focal length 15 cm are placed in contact. The power of this combination in dioptres is

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+1.5

– 1.5

+ 6.67

– 6.67

answer is D.

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Detailed Solution

$\frac{1}{f} = \frac{1}{f_{1}} + \frac{1}{f_{2}} + \frac{1}{f_{3}} = \frac{1}{40} + \frac{1}{- 40} + \frac{1}{- 15} = \frac{- 1}{15} P = \frac{100}{f} = \frac{100}{- 15} = - 6.67 D$

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