A dipole has its moment p, is kept at the centre of a ring of radius, R and charge, q. The dipole moment has its direction along the axis of the ring. The resultant force on the ring due to the dipole is

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$\frac{p q}{4 π ε_{0} R^{3}}$

$\frac{p q}{2 π ε_{0} R^{3}}$

$\frac{3 p q}{4 π ε_{0} R^{3}}$ only if the charge is uniformly distributed on the ring

answer is B.

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Detailed Solution

The field due to dipole on the circumference of ring is $E = \frac{1}{4 π \in_{0}} (\frac{P}{R^{3}})$ and it is directed normal to the frame of ring.

Hence force on the charged ring $F = q E$

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