(A) : Electron affinity of oxygen is less than nitrogen but larger than fluorine.
(R) : Atomic size increases and non metallic character decreases in a period from left to right.

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(A) is true but (R) is false

Both (A) and (R) are true but (R) is not the correct explanation of (A)

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are false

answer is D.

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Detailed Solution

Electron affinity of N is essentially zero because of its exactly half-filled electronic configuration.
Further because F has 7 electrons and O has 6 electrons in the valence shell, therefore the tendency of F to acquire additional electron is higher than that of O, i.e., EA of F is higher than that O. In other words, EA decreases as F > O > N.

In a period from left to right, non metallic character increases as atomic size decreases.

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