(A) : For projection angle tan^-1 (4), the horizontal range and the maximum height of a projectile are equal.
(R) : The maximum range of projectile is directly proportional to square of velocity and inversely proportional to acceleration due to gravity.

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(A) is true but (R) is false

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are false

Both (A) and (R) are true and (R) is not the correct explanation of (A)

answer is B.

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Detailed Solution

$R = \frac{u^{2} \sin 2 θ}{g}$ ; $H_{max} = \frac{u^{2} \sin^{2} θ}{2 g}$

$R = H_{max}$

$\Rightarrow \frac{2 u^{2} sinθcosθ}{g} = \frac{u^{2} \sin^{2} θ}{2 g}$

$\Rightarrow θ = \tan^{- 1} 4$

$R_{\max} = \frac{u^{2}}{g}$

Both (A) and (R) are true and (R) is not the correct explanation of (A).

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