(A) : Gauss’s law can’t be used to calculate electric field near an electric dipole.
(R) : Electric dipole don’t have symmetric charge distribution.

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Both ‘A’ and ‘R’ are true and ‘R’ is the correct explanation of ‘A’.

‘A’ is false and ‘R’ is false

Both ‘A’ and ‘R’ are true and ‘R’ is not the correct explanation of ‘A’

‘A’ is true and ‘R’ is false

answer is A.

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Detailed Solution

Gauss's law is applicable for any closed surface. Gauss's law is most useful in situation where the charge distribution has spherical or cylindrical symmetry or is distributed uniformly over the plane. Whereas electric dipole is a system of two equal and opposite point charges separated by a very small and finite distance.

Electric dipoles have no surface that have a symmetric distribution of electric field around, thus Gauss' Law cannot be used for the task.

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