(A) : Horizontal range is same for angle of projection $θ$ and (90^o - $θ$ ) for same speed of projection.
(R) : Horizontal range is independent of angle of projection.

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(A) is true but (R) is false

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are false

Both (A) and (R) are true and (R) is not the correct explanation of (A)

answer is C.

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Detailed Solution

$R = \frac{u^{2} \sin 2 θ}{g}$

If the initial velocity is same, then for projections at complementary angles , ranges are same.

(A) is true but (R) is false.

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