A : If $\overline{\mathrm{a}}, \overline{\mathrm{b}}, \overline{\mathrm{c}}$ form a left handed orthogonal system such that

$\overline{\mathrm{a}}.\overline{\mathrm{a}} = 4, \overline{\mathrm{b}}.\overline{\mathrm{b}}=9, \overline{\mathrm{c}}.\overline{\mathrm{c}}=16 =>[\overline{\mathrm{a}} \overline{\mathrm{b}} \overline{\mathrm{c}} ]=-24$

R : For left handed system $[\overline{\mathrm{a}} \overline{\mathrm{b}} \overline{\mathrm{c}}] <0$ , and $\overline{\mathrm{a}}.\overline{\mathrm{a}}=|\overline{\mathrm{a}}{|}^2$; for orthogonal vectors $\overline{\mathrm{a}}, \overline{\mathrm{b}}, \overline{\mathrm{c}}; [\overline{\mathrm{a}} \overline{\mathrm{b}} \overline{\mathrm{c}}]=\pm \left(\right|\overline{\mathrm{a}}|·|\overline{\mathrm{b}}|·|\overline{\mathrm{c}}\left|\right)$

The correct answer is