Q.

A man of mass 70 kg ascends a flight of 36 steps each 20 cm high. Work done by the man against the gravitational force is ((g=9.8 ms2)                                  

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a

4000 J

b

4939.2 J

c

4900 J

d

490 J

answer is A.

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Detailed Solution

Mass m=70kg

Distance S=36×20cm=36×20×102m

Acceleration due to gravity g=9.8ms2                     

W=F.S=m×a×s

=70×9.8×36×20×102

=4939.2

W=4939.2 J

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A man of mass 70 kg ascends a flight of 36 steps each 20 cm high. Work done by the man against the gravitational force is ((g=9.8 ms−2)