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A man of mass 70 kg ascends a flight of 36 steps each 20 cm high. Work done by the man against the gravitational force is ( $(g = 9 {.8 ms}^{- 2})$

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4000 J

4939.2 J

4900 J

490 J

answer is A.

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Detailed Solution

Mass m = 70kg

$Distance S = 36 \times 20cm = 36 \times 20 \times 10^{- 2} m$

$Acceleration due to gravity g = 9 {.8ms}^{- 2}$

$W = F .S = m \times a \times s$

$= 70 \times 9.8 \times 36 \times 20 \times 10^{- 2}$

$= 4939.2$

$W = 4939 .2 J$

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