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A mixture contains $16 g$ of oxygen, $28 g$ of nitrogen and $8 g$ of methane. Total pressure of the mixture is $740 m m .$ What is the partial pressure of nitrogen in mm?

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555

370

185

740

answer is B.

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Detailed Solution

$P_{N_{2}} = X_{N_{2}} P$

$= \frac{n_{N_{2}}}{n_{N_{2}} + n_{O_{2}} + n_{C H_{4}}} P$

$P_{N_{2}} = \frac{\frac{28}{28}}{\frac{28}{28} + \frac{16}{32} + \frac{8}{16}} \times 740$

$= \frac{1}{1 + 0.5 + 0.5} \times 740$

$= \frac{1}{2} \times 740$

$\begin{matrix} P_{N_{2}} = 370 m m \end{matrix}$

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