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(A) : NCl3 is known, but not NCl5.
(R) : Nitrogen can not expand its valency beyond four.

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(A) is true and (R) is false

Both (A) and (R) are true. (R) properly ex- plain (A)

(A) is false and (R) is true

Both (A) and (R) are true. (R) does not ex- plain (A)

answer is A.

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Detailed Solution

Only three orbitals are available for bonding and it cannot expand its octet.
Hence NCl₅ is not possible. Hence, in the case of Nitrogen, NCl₃ is possible but not NCl₅

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