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Q.

A particle moving with uniform acceleration along x–axis is at

x1=10 m and x2=20 m at t = 6 s and t = 10 s respectively. If its velocity

at t = 6 s is 0.5 ms−1 , then its acceleration is

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a

1 ms−2

b

2 ms−2

c

0.5 ms−2

d

0.8 ms−2

answer is C.

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Detailed Solution

Distance travelled s = 10m, Initial velocity u=0ms−1

Time taken t = 6s , Final velocity v=0.5ms−1

10=ut+12a.36⇒a=1018=0.5ms2

a=0.5ms−2

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