A particle moving with uniform acceleration along x–axis is at x1=10 m and x2=20 m at t = 6 s and t = 10 s respectively. If its velocity at t = 6 s is 0.5 ms−1 , then its acceleration is

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A particle moving with uniform acceleration along x–axis is at

$x_{1} = 10 m$ and $x_{2} = 20 m$ at t = 6 s and t = 10 s respectively. If its velocity

at t = 6 s is $0.5 {ms}^{- 1}$ , then its acceleration is

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1 {ms}^{- 2}

2 {ms}^{- 2}

0.5 {ms}^{- 2}

0.8 {ms}^{- 2}

answer is C.

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Detailed Solution

Distance travelled s = 10m, Initial velocity

u = 0 {ms}^{- 1}

Time taken t = 6s , Final velocity $v = 0.5 {ms}^{- 1}$

$10 = ut + \frac{1}{2} a .36 \Rightarrow a = \frac{10}{18} = 0.5 {ms}^{2}$

$a = 0.5 {ms}^{- 2}$

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