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A particle of mass 0.3 kg is subjected to a force $F = - k x$ with $k = 15 N / m$ . What will be its initial acceleration if it is released from a point 20 cm away from the origin?

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$3 m / s^{2}$

$15 m / s^{2}$

$5 m / s^{2}$

$10 m / s^{2}$

answer is D.

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Detailed Solution

F = -KX

K=m $ω^{2}$

15 = 0.3 $\times ω^{2}$

$ω^{2} = 50$

acleration at 20 cm is a=- $ω^{2} x = - 50 \times 0.2 = - 10 m s^{- 2}$

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