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A particle of mass m moving with a velocity $(3 \hat{i} + 2 \hat{j}) m/s$ collides with stationary body of mass M and finally moves with velocity $(- 2 \hat{i} + \hat{j}) m/s$ .Then:

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Impulse received by

M = m (5 \hat{i} + \hat{j})

Impulse received by

m = m (5 \hat{i} - 5 \hat{j})

Impulse received by

m = m (- 5 \hat{i} - \hat{j})

Impulse received by

M = m (5 \hat{i} - \hat{j})

answer is C.

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Detailed Solution

Impulse of

m = m (v - u)

$u = 3 i + 2 j, v = (- 2 i + j)$

$= m (- 2 i + j - 3 i - 2 j)$

$= m (- 5 i - j)$

Impulse of $M = - m (v - u)$

$= m (5 i + j)$

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A particle of mass m moving with a velocity (3 i^+2j^) m/s collides with stationary body of mass M and finally moves with velocity (−2 i^+j^) m/s .Then:

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A particle of mass m moving with a velocity $(3 \hat{i} + 2 \hat{j}) m/s$ collides with stationary body of mass M and finally moves with velocity $(- 2 \hat{i} + \hat{j}) m/s$ .Then: