A point charge is placed at origin. Let $\overrightarrow{E_A},\overrightarrow{E_B}$  and $\overrightarrow{E_C}$ be the electric field at three points A (1,2,3), B (1,1,-1) and C (2,2,2) due to charge $q_1$ then

$\overrightarrow{E_A}$  is along $\overrightarrow{OA}$  and           $\overrightarrow{E_B}$  is along $\overrightarrow{OB}$

$\overrightarrow{OA}=i+2j+3k$  and           $\overrightarrow{OB}=i+j-k$

Since $\overrightarrow{OA.}\overrightarrow{OB}=0$                  $\overrightarrow{E_A}\perp \overrightarrow{E_B}$

Further $\left|\overrightarrow{E}\right|$ $\alpha \frac{1}{r^2}$                    $\left|\overrightarrow{OC}\right|$ =$2\left|\overrightarrow{OB}\right|$

                                              $\left|\overrightarrow{E_B}\right|=4\left|\overrightarrow{E_C}\right|$