Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

(A) : Pressure of the gas increases with the decrease in volume at constant temperature
(R) : Number of molecules per unit volume increases with decrease in volume consequently number of collisions on the wall increases

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

Both (A) and (R) are correct and (R) is the correct explanation of (A)

b

(A) is True but (R) is False.

c

Both (A) and (R) are false

d

Both (A) and (R) are correct but (R) is not the correct explanation of (A)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

We know that,

 PV=nRT At constant T, PV=constant P α 1V

Hence, as pressure increases, volume decreases at constant temperature.

The pressure on the walls is due to the collisions of gas molecules on the it. 

As the space occupied by these molecules.i.e., their volume decreases, more number of molecules compete for the space, resulting in increase in collisions on the wall.

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon