Q.

(A) : Pressure of the gas increases with the decrease in volume at constant temperature
(R) : Number of molecules per unit volume increases with decrease in volume consequently number of collisions on the wall increases

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

Both (A) and (R) are correct and (R) is the correct explanation of (A)

b

(A) is True but (R) is False.

c

Both (A) and (R) are false

d

Both (A) and (R) are correct but (R) is not the correct explanation of (A)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We know that,

 PV=nRT At constant T, PV=constant P α 1V

Hence, as pressure increases, volume decreases at constant temperature.

The pressure on the walls is due to the collisions of gas molecules on the it. 

As the space occupied by these molecules.i.e., their volume decreases, more number of molecules compete for the space, resulting in increase in collisions on the wall.

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
(A) : Pressure of the gas increases with the decrease in volume at constant temperature(R) : Number of molecules per unit volume increases with decrease in volume consequently number of collisions on the wall increases