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A pump of certain power is lifting $3 k g$ water per second from an average depth of $10 m$ . The velocity with which water comes out of the pump is $4 m s^{- 1}$ $(g = 10 m s^{- 2})$ . Find the power

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$234 w$

$324 w$

$432 w$

$400 w$

answer is B.

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Detailed Solution

$p = \frac{m g h + \frac{1}{2} m v^{2}}{t} = \frac{3 \times 10 \times 10 + \frac{1}{2} \times 3 \times 16}{1} = 300 + 24 = 324 w$

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