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A series AC circuit has a resistance of $12 Ω$ and a reactance of $5 Ω$ . The impedance of the circuit is

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$13 Ω$

$\frac{17}{60} Ω$

$60 Ω$

$17 Ω$

answer is B.

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Detailed Solution

$Z = \sqrt{R^{2} + X^{2}} = \sqrt{12^{2} + 5^{2}} = \sqrt{144 + 25} = \sqrt{169} = 13 Ω$ .

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