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Q.

A series LCR circuit is tuned to resonance. The impedance of the circuit now is

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a

[R2+(ωL1ωC)2]1/2

b

[R2+(ωL+1ωC)2]1/2

c

[R2+(1ωCωL)2]1/2

d

R

answer is D.

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Detailed Solution

 Impedance of the LCR circuit is give n b Z=R2+(ωL1ωc)2 At resonanance impedance of the circuit is minimum and it is equal to resistanceR.

Z=R 

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