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A stone is projected from a point on ground at some angle of projection. At the same time, a bee starts from a point directly above this point of projection at a height of 2.5m horizontally with speed $5 \sqrt{2} m s^{- 1}$ . It is found that the stone just touches the bee at one point. Find range of projectile motion of stone

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10m

7.5m

2.5m

answer is A.

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Detailed Solution

Here $H = \frac{u^{2} \sin^{2} α}{2 g}$ $\Rightarrow 2.5 = \frac{u^{2} \sin^{2} α}{20}$

Or $u \sin α = \sqrt{50}$ And $u \cos α = 5 \sqrt{2}$

$∴ R = \frac{2 u \sin α u \cos α}{g} = \frac{2 \times \sqrt{50} \times 5 \sqrt{2}}{10} = 10 m$

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