Q.

A stretched string of length 2m vibrates in 4  segments.  The distance between consecutive nodes is

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a

0.5m

b

0.25m

c

0.75m

d

1.0m

answer is A.

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Detailed Solution

Given length of the string l=2m 

Number of segments n=4

The distance between consecutive nodes l=nλ2

l=4λ2

2=2λ

λ=1

The distance for one segment l=λ2

                                                        =12

                                                      =0.5m

 

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