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(A) : The line 3x + 4y – 12 = 0 meets the circle $x^{2} + y^{2} = 24$ at A and B. If the tangents at A and B to the circle intersect at P then P = ( 6, 8)
(R) : The pole of the line $l x + m y + n = 0$ w.r.t $x^{2} + y^{2} = r^{2}$ is $(\frac{- r^{2} l}{n}, \frac{- r^{2} m}{n})$

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Both A and R are true and R explains A

Both A and R are true but R doesn't explain A

A is true but R is false

A is false but R is true

answer is A.

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Detailed Solution

A: Given pole of the line 3x+4y-12=0 w.r.to the circle $x^{2} + y^{2} = 24 i s (6, 8)$

R: $p o l e o f t h e l i n e lx + my + n = 0 w . r . to x^{2} + y^{2} = r^{2} is (\frac{- r^{2} l}{n}, \frac{- r^{2} m}{n})$

Both A and R true and R is correct explanation of A.

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