(A) : The surface charge densities of two spherical conductors of different radii are equal. Then the electric field intensities near their surface are also equal.
(R) : Surface charge density is equal to charge per unit area.

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Both ‘A’ and ‘R’ are true and ‘R’ is the correct explanation of ‘A’.

‘A’ is false and ‘R’ is false

Both ‘A’ and ‘R’ are true and ‘R’ is not the correct explanation of ‘A’

‘A’ is true and ‘R’ is false

answer is B.

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Detailed Solution

The surface charge densities of two spherical conductors of different radii are equal. Then the electric field intensities near their surface are also equal.

$σ_{A} = σ_{B}$

$\Rightarrow \frac{Q_{A}}{{4 π R_{A}}^{2}} = \frac{Q_{B}}{{4 π R_{B}}^{2}}$

$\Rightarrow \frac{Q_{A}}{{4 π ε_{0} R_{A}}^{2}} = \frac{Q_{B}}{{4 π ε_{0} R_{B}}^{2}}$

$\Rightarrow E_{A} = E_{B}$

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