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(A) : The surface densities of two spherical conductors of different radii are equal. Then the electric field intensities near their surface are also equal.
(R) : Surface density is equal to charge per unit area.

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'A' is true and 'R' is false

Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A'

Both 'A' and 'R' are true and 'R' is the correct explanation of 'A'.

'A' is false and 'R' is true

answer is B.

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Detailed Solution

(A) $σ_{1} = σ_{2}$

$\frac{q_{1}}{4 π r^{2}} = \frac{q_{2}}{4 π R^{2}}$

$\frac{q_{1}}{q_{2}} = \frac{r^{2}}{R^{2}}$

$\Rightarrow \frac{E_{1}}{E_{2}} = \frac{q_{1}}{4 π \in_{0} r^{2}} \times \frac{4 π \in_{0} R^{2}}{q_{2}}$

$\Rightarrow E_{1} = E_{2}$

Assertion is true

(R) $σ = \frac{q}{A}$

The correct option is B

But the reason is not the correct explanation of the Assertion.

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