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A transistor having a $β$ equal to 80 has a change in base current of 250 $μ A$ , then the change in collector current is:

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200 mA

2000 mA

20,000 mA

20 mA

answer is D.

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Detailed Solution

$β = (\frac{Δ i_{C}}{Δ i_{B}})$

$80 = \frac{Δ i_{C}}{250 \times 10^{- 6}}$

$Δ i_{C} = 80 \times 250 \times 10^{- 6}$

$Δ i_{C} = 20000 \times 10^{- 6}$

$= 20 \times 10^{- 3} = 20 m A$

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