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A wave of frequency $200 Hz$ is sent along a string towards a fixed end. When this wave travels back then after reflection, a node is formed at a minimum distance of $5 cm$ from the fixed end of the string. The speed of the incident wave is

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$10 m/s$

$40 m/s$

$20 m/s$

$5 m/s$

answer is A.

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Detailed Solution

Frequency $n = 200 Hz$

Length $l = 5 cm$

As $l = \frac{λ}{2}$

$5 = \frac{λ}{2}$

$λ = 10 cm$

$v = n λ$

$= 200 \times 10$

$= 2000 cm/s$

$= 20 m/s$

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