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Q.

A 0.0020 m aqueous solution of a ionic compound $C o {(N H_{3})}_{5} N O_{2}$ freezes at $- {0.00732}^{o} C$ what will be the number of moles of ions which 1 mol of ionic compound produces $(K_{f} = {1.86}^{o} C/m)$ . (round of to the nearest integer)

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answer is 2.

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Detailed Solution

$Δ T_{f} = {iK}_{f} m$

$∴ i = \frac{{ΔT}_{f}}{K_{f} ×m} = \frac{0.00732}{1.86 \times 0.002} = 2$

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