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Q.

A 0 .1 k g mass is suspended from a wire of negligible mass. The length of the wire is 1 m and its cross-sectional area is 4.9×107m2. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140rads1. If the Young’s modulus of the material of the wire is n×109Nm2, the value of n is. 

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answer is 4.

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Detailed Solution

When a wire of length L, area of cross-section A, Young’s modulus Y is
stretched by suspending a mass m , then the mass performs simple harmonic
motion with angular frequency ω=YAmL Substituting the given values, we get

140=n×109×4.9×1070.1×1 or  

140×140=n×109×4.9×1070.1×1

n=14×14×10249×102=4

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