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A 0.25 molal aqueous solution of $C o C l_{3} {(N H_{3})}_{4}$ freezes at $- {0.93}^{0} C$ . Then the number of stereoisomers for this coordination compound is____
(Given that: Molal depression constant for $H_{2} O$ is K/molal and assume complete dissociation of the coordination compound into its ions)

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answer is 2.

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Detailed Solution

$Δ T_{f} = i \times k_{f} \times m 0.93 = i \times 1.86 \times 0.25 i = 2$
Complex is: $[C o C l_{2} {(N H_{3})}_{4}] C l$
${[C o C l_{2} {(N H_{3})}_{4}]}^{+}$ has two geometrical isomers and both cis and trans isomers are optically inactive.

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